2=0.005x^2

Solution for 2=0.005x^2 equation:

2=0.005x^2

We move all terms to the left:

2-(0.005x^2)=0

We get rid of parentheses

-0.005x^2+2=0

a = -0.005; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-0.005)·2
Δ = 0.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.04}}{2*-0.005}=\frac{0-\sqrt{0.04}}{-0.01}
=-\frac{\sqrt{}}{-0.01}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.04}}{2*-0.005}=\frac{0+\sqrt{0.04}}{-0.01}
=\frac{\sqrt{}}{-0.01}
$